If θ is an acute angle and sin θ cos θ = 2 cos3 \(θ-\frac{1}{4} \cos θ\), then the value of sin θ is:

1
\(\frac{\sqrt{15}-1}{8}\)
2
\(\frac{\sqrt{15}-1}{4}\)
3
\(\frac{\sqrt{15}+1}{4}\)
4
\(\frac{\sqrt{15}-1}{2}\)

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