On simplification of expression:

\(Y = \overline {\left( {A.B + \bar C} \right)\left( {\overline {A + B} + C} \right)} \), using Boolean algebra, the solution is:

1
(A. B + C) (A + B . C)
2
(A̅ + B̅ + C̅ ) (A + B + C)
3
(A . B + C̅ ) (A . C + B̅ )
4
(B . C + A̅ ) (A . B + C̅ )

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