If \(2\frac{{{{\cos }^2}x - {{\sec }^2}x}}{{{{\tan }^2}x}} = \) a + b cos 2 x, then a, b = ?

1
\(\frac{{ - 3}}{2},\frac{{ - 1}}{2}\)
2
\(\frac{3}{2},\frac{1}{2}\)
3
-3, -1
4
3, 1

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