ΔABC ∼ ΔQRP. If the ratio of the area of ΔABC to the area of ΔPQR is 576 ∶ 169, AB = 10 cm, AC = 12 cm and BC = 13 cm, then the length of PR (in cm) is equal to:    

1
\(\dfrac{169}{11}\)
2
\(\dfrac{169}{10}\)
3
\(\dfrac{169}{12}\)
4
\(\dfrac{169}{24}\)

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