If y1 and y2 are depth of flow before and after the hydraulic jump in a rectangular channel then the loss of energy is given by
1
\(\frac{{{{\left( {{{\rm{y}}_{\rm{2}}}{\rm{ - }}{{\rm{y}}_{\rm{1}}}} \right)}^{\rm{2}}}}}{{{{\rm{y}}_{\rm{1}}}{{\rm{y}}_{\rm{2}}}}}\)
2
\(\frac{{{{\left( {{{\rm{y}}_{\rm{2}}}{\rm{ - }}{{\rm{y}}_{\rm{1}}}} \right)}^{\rm{3}}}}}{{{{\rm{y}}_{\rm{1}}}{{\rm{y}}_{\rm{2}}}}}\)
3
\(\frac{{{{\left( {{{\rm{y}}_{\rm{2}}}{\rm{ - }}{{\rm{y}}_{\rm{1}}}} \right)}^{\rm{3}}}}}{{{\rm{4}}{{\rm{y}}_{\rm{1}}}{{\rm{y}}_{\rm{2}}}}}\)
4
\(\frac{{{{\left( {{{\rm{y}}_{\rm{2}}}{\rm{ - }}{{\rm{y}}_{\rm{1}}}} \right)}^{\rm{3}}}}}{{{\rm{8}}{{\rm{y}}_{\rm{1}}}{{\rm{y}}_{\rm{2}}}}}\)