For a single phase transformer, the maximum efficiency occurs at 75% of the load, then \(\rm \frac{iron \ loss \ at\ full \ load }{copper \ loss \ at\ full \ load}=?\)

1
\(\frac{3}{4}\)
2
\(\frac{16}{10}\)
3
\(\frac{16}{25}\)
4
\(\frac{9}{16}\)

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