Determine the values of Rth and Isc that cause the given circuit to be the Norton equivalent circuit.

1
Rt = 6Ω, Isc = 0.25 A 
2
Rt = 8Ω, Isc = 0.5 A
3
Rt = 8Ω, Isc = 0.25 A
4
Rt = 6Ω, Isc = 0.5 A

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