Let ABC be a triangle right angled at B. If tan A = \(\frac{12}{5}\), then find the values of cosec A and sec A, respectively.

1
\(\frac{13}{10},\frac{5}{13}\)
2
\(\frac{13}{12},\frac{13}{5}\)
3
\(\frac{10}{13},\frac{5}{13}\)
4
\(\frac{12}{13},\frac{5}{13}\)

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