Thirty men can do a piece of work in 16 days working 8 hrs a day. How many men are needed to complete another work, which is twice the first one, in 10 days working 12 hrs a day?
The following are the steps involved in solving the above problem. Arrange them in sequential order.
A) M2 = \(\rm\frac{30 \times 16 \times 8 \times 2x}{x \times 12 \times 10}\)
B) \(\rm\frac{30 \times 16 \times 8}{x}=\frac{M_2 \times 12 \times 10}{2 x}\)
C) \(\rm\frac{M_1 D_1 H_1}{ W_1}=\frac{M_2 D_2 H_2}{W_2}\)
D) M2 = 64
1
ACBD
2
ABCD
3
BACD
4
CBAD