From the top of an upright pole 17.75 m high, the angle of elevation of the top of an upright tower was 60⁰. If the tower was 57.75 m tall, how far away (in m) from the foot of the pole was the foot of the tower?

1
\(40\sqrt3\)
2
\(\frac{151\sqrt3}{6}\)
3
\(\frac{77}{4}\sqrt3\)
4
\(\frac{40\sqrt3}{3}\)

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