If \(\frac{\secθ - \tanθ}{\secθ + \tanθ} = \frac{1}{9}\), θ lies in the first quadrant, then the value of \(\frac{\sinθ - \tan^2θ}{\sinθ + \tan^2θ}\) is:

1
\(-\frac{13}{27}\)
2
\(\frac{13}{27}\)
3
\(\frac{11}{29}\)
4
\(-\frac{11}{29}\)

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