Let Δ ABC ∼ Δ RPQ and \(\frac{ar(\Delta ABC)}{ar(\Delta RPQ)}=\frac{16}{25}\). If PQ = 4 cm, QR = 6 cm and PR = 7 cm, then AC (in cm) is equal to:

1
4.8
2
6
3
3.6
4
7.2

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