A block is kept on a frictionless inclined surface with angle of inclination 60°. The incline is given an acceleration 'a' to keep the block stationary. Then 'a' is equal to

1
\(\frac{{\sqrt 3 g}}{2}\)
2
\(\frac{{2g}}{{\sqrt 3 }}\)
3
\(\sqrt 3 \)g
4
\(\frac{g}{{\sqrt 3 }}\)

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