"m" men and "n" women are to be seated in a row so that no two women sit together. If m > n, then
number of ways in which they can be seated, is
1
\(\frac{\lfloor m \mid m-1}{\lfloor m-n+1}\)
2
\(\frac{\lfloor m-1 \mid m+1}{\lfloor n\lfloor n-1} \)
3
\(\frac{\lfloor m \mid m+1}{\lfloor m-n+1}\)
4
\(\frac{\lfloor m \mid m-1}{\lfloor m-n-1}\)
5
Question Not Attempted