There are two AP’s. The first term of the second AP is 37. The third term of the 1st AP is 10 more than the 5th term of the second AP. The 4th term of the second AP is one more than the 1st term of the 1st AP. If the third term of the second AP is 47. Find the third term of the 1st AP.

1
67
2
61
3
69
4
56

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