When two inductors L1 and L2 are connected in parallel with opposing mutual inductance M then the combined inductance is

1
\({{\rm{L}}_1} + {{\rm{L}}_2} + 2M\)
2
\({L_{eq}} = \frac{{{{\rm{L}}_1}.{{\rm{L}}_2} - {M^2}}}{{{{\rm{L}}_1} + {{\rm{L}}_2} - 2M}}\)
3
\({L_{eq}} = \frac{{{{\rm{L}}_1}.{{\rm{L}}_2} - {M^2}}}{{{{\rm{L}}_1} + {{\rm{L}}_2} + 2M}}\)
4
\({{\rm{L}}_1} + {{\rm{L}}_2} - 2M\)

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