The 2s orbital of H-atom has a radial node at 2a0 because ψ2s is proportional to

1
\(\left(\dfrac{1}{2}+\dfrac{r}{a_0}\right)\)
2
\(\left(2+\dfrac{r}{a_0}\right)\)
3
\(\left(2-\dfrac{r}{a_0}\right)\)
4
\(\left(2-\dfrac{r}{2a_0}\right)\)

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