If 5a + \(\frac{1}{3a} \) = 5, then the value of 9a2\(\frac{1}{25a^2} \) is:

1
\(\frac{51}{5} \)
2
\(\frac{29}{5} \)
3
\(\frac{52}{5} \)
4
\(\frac{39}{5} \)

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