If 5 tan θ = 4, then \(\frac{{{\rm{5}}\,{\rm{sin}}\,{\rm{\theta }}\,{\rm{ - }}\,{\rm{3}}\,{\rm{cos}}\,{\rm{\theta }}}}{{{\rm{5}}\,{\rm{sin}}\,{\rm{\theta }}\,{\rm{ + }}\,{\rm{2}}\,{\rm{cos}}\,{\rm{\theta }}}}\) =

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