Teaching Jharkhand (JSSC) TGT (6 to 8) Mock Test 2023-24 Engineering Mathematics Calculus Definite Integrals
\(\rm\displaystyle\int_0^{\frac{\pi}{4}} \frac{d x}{\cos ^3 x \sqrt{2 \sin 2x}}\) = _______
1
\(\frac{6}{5}\)
2
\(\frac{3}{5}\)
3
\(\frac{1}{5}\)
4
\(\frac{2}{5}\)