Find the equation of the hyperbola whose foci are at (0, ± 6) and the length of whose conjugate axis is 2√11 ?

1
\(\frac{{{y^2}}}{{{21}}} - \frac{{{x^2}}}{{{11}}} = 1\)
2
\(\frac{{{y^2}}}{{{25}}} - \frac{{{x^2}}}{{{11}}} = 1\)
3
\(\frac{{{y^2}}}{{{16}}} - \frac{{{x^2}}}{{{11}}} = 1\)
4
\(\frac{{{y^2}}}{{{5}}} - \frac{{{x^2}}}{{{11}}} = 1\)

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