An urn contains 6 different white balls and 4 different black balls. A fair die is thrown and that number of balls as appears on the die are chosen from the urn. Then the probability that the balls chosen are white, is

1
\(\frac{1}{5}\)
2
\(\frac{1}{7}\)
3
\(\frac{1}{8}\)
4
\(\frac{1}{6}\)

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