Let \(f(x) = \left| {\begin{array}{*{20}{c}} {{x^3}}&{\sin x}&{\cos x}\\ 6&{ - 1}&0\\ p&{{p^2}}&{{p^3}} \end{array}} \right|\), where p is a constant, then \(\frac{{{d^3}}}{{d{x^3}}}\left( {f(x)} \right)\) at x = 0 is

1
p
2
p + p2
3
p + p3
4
independent of p

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