If the system of equation 2x + 3y + 5 = 0, x + ky + 5 = 0, kx - 12y - 14 = 0 be consistent, then the values of k are - 

1
\(6, \ \dfrac{-17}{5}\)
2
\(-1, \ \dfrac{1}{5}\)
3
\(-6, \ \dfrac{17}{5}\)
4
\(6, \ \dfrac{-12}{5}\)
5
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