If \(A=\left\{x: \frac{\pi}{6} \leq x \leq \frac{\pi}{3}\right\}\) and f : A → R is given by f(x) = cos x - x(1 + x), then f(A) is equal to
1
[π/6, π/3]
2
[-π/3, -π/6]
3
\(\left[\frac{1}{2}-\frac{\pi}{3}\left(1+\frac{\pi}{3}\right), \frac{\sqrt{3}}{2}-\frac{\pi}{6}\left(1+\frac{\pi}{6}\right)\right]\)
4
\(\left[\frac{1}{2}+\frac{\pi}{3}\left(1-\frac{\pi}{3}\right), \frac{\sqrt{3}}{2}+\frac{\pi}{6}\left(1-\frac{\pi}{6}\right)\right] \)
5
Question Not Attempted