If g(x) = x2 + x – 1 and (gof)(x) = 4x2 – 10x + 5, then \(f\left(\frac{5}{4}\right) \) is equal to

1
\(-\frac{3}{2}\)
2
\( -\frac{1}{2}\)
3
\(\frac{1}{2}\)
4
\(\frac{3}{2}\)
5
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