The inverse Laplace transform of \(H\left( s \right) = \ln \left( {\frac{1}{{s + 4}}} \right)\) is

1
\(\frac{{ - {e^{4t}}}}{t}u\left( t \right)\)
2
\(\frac{{ - {e^{ - 4t}}}}{t}u\left( t \right)\)
3
\(\frac{{{e^{ - 4t}}}}{t}u\left( t \right)\)
4
\(\frac{{{e^{4t}}}}{t}u\left( t \right)\)

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