If \(\rm\displaystyle\int \frac{d x}{(x+2)\left(x^2+1\right)}\) = a log |1 + x2| + b tan−1x + \(\frac{1}{5}\) log |x + 2| + C, then

1
a = \(\frac{−1}{10}\), b = \(\frac{−2}{5}\)
2
a = \(\frac{1}{10}\), b = \(−\frac{2}{5}\)
3
a = \(\frac{−1}{10}\), b = \(\frac{2}{5}\)
4
a = \(\frac{1}{10}\), b = \(\frac{2}{5}\)

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