\(\sin θ =-\dfrac{4}{5}\) and θ lies in the third quadrant, then \(\cos \dfrac{\theta}{2}\) is equal to:

1
\(\dfrac{1}{\sqrt{5}}\)
2
\(-\dfrac{1}{\sqrt{5}}\)
3
\(\sqrt{\dfrac{2}{5}}\)
4
\(-\sqrt{\dfrac{2}{5}}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation