In ΔABC and Δ DEF, AB = 5 cm, AC = 7 cm, ∠A = 90°, FD = 5 cm, EF = 7 cm and ∠F = 90°. Then,

1
ΔABC \(\cong\) ΔEDF, by RHS congruence rule
2
ΔABC \(\cong\)ΔDEF, by RHS congruence rule
3
ΔABC \(\cong\) ΔEDF, by SAS congruence rule
4
ΔABC \(\cong\)ΔFDE, by SAS congruence rule
5
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