Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown below at time t = 0. If the charge on capacitors A and B at time t = CR is QA and QB respectively, then (Here e is the base of natural logarithm)
1
QA = VC, QB = CV
2
\(\mathrm{Q}_{\mathrm{A}}=\frac{\mathrm{CV}}{2}, \mathrm{Q}_{\mathrm{B}}=\frac{\mathrm{VC}}{\mathrm{e}}\)
3
\(\mathrm{Q}_{\mathrm{A}}=\frac{\mathrm{VC}}{\mathrm{e}}, \mathrm{Q}_{\mathrm{B}}=\frac{\mathrm{CV}}{2}\)
4
\(\mathrm{Q}_{\mathrm{A}}=\mathrm{VC}, \mathrm{Q}_{\mathrm{B}}=\frac{\mathrm{VC}}{\mathrm{e}}\)