Teaching UKPSC Lecturer Mock Test Series 2024 Physics Semiconductors Digital Electronics and Logic Gates
In the following circuit, the output Y for all possible inputs and B is expressed by the truth table:
1
\(\begin{array}{l} A\\ 0\\ 0\\ 1\\ 1 \end{array}\)\(\begin{array}{l} B\\ 0\\ 1\\ 0\\ 1 \end{array}\)\(\begin{array}{l} Y\\ 0\\ 0\\ 0\\ 1 \end{array}\)
2
\(\begin{array}{*{20}{l}} A\\ 0\\ 0\\ 1\\ 1 \end{array}\begin{array}{*{20}{l}} B\\ 0\\ 1\\ 0\\ 1 \end{array}\begin{array}{*{20}{l}} Y\\ 1\\ 1\\ 1\\ 0 \end{array}\)
3
\(\begin{array}{*{20}{l}} A\\ 0\\ 0\\ 1\\ 1 \end{array}\begin{array}{*{20}{l}} B\\ 0\\ 1\\ 0\\ 1 \end{array}\begin{array}{*{20}{l}} Y\\ 1\\ 0\\ 0\\ 0 \end{array}\)
4
\(\begin{array}{*{20}{l}} A\\ 0\\ 0\\ 1\\ 1 \end{array}\begin{array}{*{20}{l}} B\\ 0\\ 1\\ 0\\ 1 \end{array}\begin{array}{*{20}{l}} Y\\ 0\\ 1\\ 1\\ 1 \end{array}\)