N identical cells, each of emf  ε and internal resistance r, are joined in series. Out of these, n cells are wrongly connected, i.e. their terminals are connected in reverse of that required for series connection. n < (N/2). Let  ε0 be the emf of the resulting battery and r0 be its internal resistance.

1
ε0 = (N – n) ε, r0 = (N – n) r
2
ε0 = (N – 2n)ε, r0 = (N – 2n)r
3
ε0 = (N – 2n)ε, r0 = Nr
4
ε0 = (N – n)ε, r0 = Nr

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