Given that A and B are second quadrant angles, sin A = \(\frac{1}{3}\) and sin B = \(\frac{1}{5}\), then find the value of cos (A − B).

1
\(\frac{4\sqrt{3}+1}{15}\)
2
\(\frac{8\sqrt{3}−1}{15}\)
3
\(\frac{8\sqrt{3}+1}{15}\)
4
\(\frac{4\sqrt{3}−1}{15}\)

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