If length of the equal sides of an isosceles triangle is a and the length of the third side is b then area of the isosceles triangle is
1
\(\sqrt {4{b^2} - {a^2}} sq.units\)
2
\(\frac{b}{4}\sqrt {4{b^2} - {a^2}} sq.units\)
3
\(\frac{b}{4}\sqrt {4{a^2} - {b^2}} sq.units\)
4
\(\frac{a}{4}\sqrt {4{a^2} - {a^2}} sq.units\)