If x = \(\left(\frac{2}{3}\right)^{-3} \div\left(\frac{9}{4}\right)^{-1}\), then the value of x-1 =

1
\(\left(\frac{3}{2}\right)^{-1}\)
2
\(\frac{3}{2}\)
3
\(\left(\frac{3}{2}\right)^{5}\)
4
\(\left(\frac{3}{2}\right)^{-5}\)

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