Changing the order of the integration in the double integral

\(I = \mathop \smallint \limits_0^{4a} \mathop \smallint \limits_{\frac{{{x^2}}}{{4a}}}^{2\sqrt {ax} } dydx\) leads to

\(\;I = \mathop \smallint \limits_p^q \mathop \smallint \limits_r^s dxdy\).

What is the value of (q × s)?

1
0
2
y2
3
\(8a\sqrt {ay}\)
4
\(\frac{{{y^2}}}{2}\sqrt {\frac{y}{a}}\)
5
Not Attempted

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation