A smooth wire of length 2πr is bent into a circle and kept in a vertical plane. A bead can slide smoothly on the wire. When the circle is rotating with angular speed ω about the vertical diameter AB, as shown in figure, the bead is at rest with respect to the circular ring at position P as shown. Then the value of ω2 is equal to:
1
\(\frac{{\sqrt 3 {\rm{g}}}}{{2{\rm{r}}}}\)
2
\(\frac{{2{\rm{g}}}}{{{\rm{r}}\sqrt 3 }}\)
3
\(\frac{{{\rm{g}}\sqrt 3 }}{{\rm{r}}}\)
4
\(\frac{{2{\rm{g}}}}{{\rm{r}}}\)