Teaching EMRS PGT Mock Test 2023 Mathematics Mathematical Reasoning

De-Morgan'w theorem is

1
\(\rm \overline{\bar{A}+\bar{B}}=\bar{A}\cdot \bar{B}\)
2
\(\rm \overline{A\cdot B}=\bar{A}+\bar{B}\)
3
\(\rm \bar{A}-\bar{B}=\bar{A}\cdot \bar{B}\)
4
\(\rm \bar{B}\cdot \bar{A}=\bar{A}+\bar{B}\)
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