Let \(f\left( x \right) = \left\{ \begin{array}{l} {x^p}\sin \frac{1}{x},x \ne 0\\ 0,\,x = 0 \end{array} \right.\) then f(x) is continuous but not differentiable at x = 0 if
1
0 < p ≤ 1
2
1 ≤ p < ∞
3
- ∞ < p < 0
4
p = 0
Let \(f\left( x \right) = \left\{ \begin{array}{l} {x^p}\sin \frac{1}{x},x \ne 0\\ 0,\,x = 0 \end{array} \right.\) then f(x) is continuous but not differentiable at x = 0 if