Two identical rods of rectangular cross-sections are placed as shown in the figure. If the length, width, and thickness of the rods are l, b, and t respectively, then the height of the center of mass of the arrangement from the bottom will be:
1
\(\frac{3l+2b}{4}\)
2
\(\frac{3l}{4}\)
3
\(\frac{l}{2}\)
4
\(\frac{3l+b}{4}\)