Let P the point of intersection of the lines \(\frac{x-2}{1}\) = \(\frac{y-4}{5}\) = \(\frac{z-2}{1}\) and \(\frac{x-3}{2}\) = \(\frac{y-2}{3}\) = \(\frac{z-3}{2}\). Then, the shortest distance of P from the line 4x = 2y = z is
1
\(\frac{5 \sqrt{14}}{7}\)
2
\(\frac{\sqrt{14}}{7}\)
3
\(\frac{3\sqrt{14}}{7}\)
4
\(\frac{6\sqrt{14}}{7}\)