Teaching NVS PGT 2024 Test Series Mathematics Differential Equations Solution of Differential Equations
Solution of given differential equation \(dy = \left( {{e^y} + {x^2}{e^y}} \right)dx\) is
1
\(y = x + {\frac{x}{3}^3} + c\)
2
\({e^{ - y}} = - x - {\frac{x}{3}^3} + c\)
3
\({e^{ - y}} = x + {\frac{x}{3}^3} + c\)
4
\(y = - x - {\frac{x}{3}^3} + c\)