If x satisfies |3x - 2| + |3x - 4| + |3x - 6| ≥ 12, then

1
x ≤ 0
2
x ≥ \(\frac{4}{3}\)
3
x ≤ 0 or x ≥ \(\frac{8}{3}\)
4
x ≥ 2

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