The value of 

\([(\frac {4}{3})^2]^3\) × \((\frac 2 3)^{-4}\) × \((\frac {27}{16})^2\) ÷ 33 is

1
3
2
\(\frac 3 4\)
3
9
4
\(\frac 9 {16}\)

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