The solution of the differential equation \(\frac{dy}{dx}=\frac{y^2}{1-3xy}\) is given by

1
\(y^3x=\frac{y^2}{2}+C\)
2
\(y^3=\frac{xy^2}{2}+C\)
3
\(x=\frac{(1+2Cy)}{y^3}\)
4
\(x=\frac{C}{y^3}\)

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