Let z ∈ ℂ and i = \(\sqrt{-1}\), if a, b, c, ∈ (0, 1) be such that a2 + b2 + c2 = 1 and b + ic = (1 + a) z, then \(\rm \frac{1+ iz}{1-iz}=\)

1
\(\rm \frac{a+ib}{1+c}\)
2
\(\rm \frac{a-ib}{1+c}\)
3
\(\rm \frac{a-ib}{1-c}\)
4
\(\rm \frac{a+ib}{1-c}\)

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