Let ϕ be the solution of

ϕ(x) = 1 − 2x − 4x2 + \(\rm \int^x_0\)[3 + 6(x − t) − 4(x − t)2]ϕ(t)dt.

Then ϕ(1) is equal to

1
e-1
2
e-2
3
e
4
e2
5
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