If A = \(\left(\begin{array}{ccc}1 & 0 & 0 \\ i & \frac{-1+i \sqrt{3}}{2} & 0 \\ 0 & 1+2 i & \frac{-1-i \sqrt{3}}{2}\end{array}\right)\) then the trace of A102 is

1
0
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1
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2
4
3
5
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