Two identical metal plates are given charges Q1 and – Q2 respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between the plates will be 

1
(Q1 + Q2) / (2C)
2
(Q1 + Q2) / C
3
(Q1 – Q2) / C
4
 (Q1 – Q2) / (2C)
5
Question Not Attempted

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